SOLUTION: factor completely: (((3x^2-2x-8)))

Question 111046This question is from textbook Intermediate Algebra
: factor completely:
(((3x^2-2x-8))) This question is from textbook Intermediate Algebra

Found 2 solutions by scott8148, oberobic:
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
(3x+4)(x-2)
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
The general form of the equation is:

To factor you have to look at the relation of a, b, and c.
In this case, we have:
a=3
b=-2
c=-8
8 can be factored only into 2*4.
Since c is negative we have a case where one factor has a + and the other has -.
3 is a prime number, so it cannot be factored.
So, the only possible solutions are:
(not what we want)
(not what we want)
(not what we want)
(what we want!!)

RELATED QUESTIONS
factor completely... (answered by Fombitz,jim_thompson5910)
factor completely... (answered by akmb1215)
i am trying to factor completely? 3x^2-26x+16... (answered by stanbon)
I need to factor the polynomial completely. 3x^3+12x^2-2x-8... (answered by richwmiller)
Please help me with thses 2 problems and thanks Factor completely:... (answered by checkley75)
Factor Completely x^2+3x+2xy+6y Factor Completely 2x^2-6xy +5x -15y (answered by MathLover1)
Factor completely: 3x2 + 2x � 8 (answered by stanbon)
Factor completely: 3x2 + 2x � 8 (answered by Alan3354)
Factor completely: 3x2 + 2x � 8 (answered by jim_thompson5910)