SOLUTION: Suppose that a cyclist began a 352 mi ride across a state at the western edge of the state, at the same time that a car traveling toward it leaves the eastern end of the

Question 1108025: Suppose that a cyclist began a 352

mi ride across a state at the western edge of the state, at the same time that a car traveling toward it leaves the eastern end of the state. If the bicycle and car met after 5.5

hr and the car traveled 32.8

mph faster than the bicycle, find the average rate of each
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Suppose that a cyclist began a 352 mi ride across a state at the western edge of the state, at the same time that a car traveling toward it leaves the eastern end of the state.
:
If the bicycle and car met after 5.5 hr and the car traveled 32.8 mph faster than the bicycle,
find the average rate of each
:
let s = the speed of the bike
then
(s+32.8) = the speed of the car
:
Both travel for 5.5 hrs and the sum of their distances is 352 mi
(dist = time * speed)
5.5s + 5.5(s+32.8) = 352
5.5s + 5.5s + 180.4 = 352
11s = 352 - 180.4
11s = 171.6
s = 171.6/11
s = 15.6 mph is the speed of the bike
then, obviously
15.6 + 32.8 = 48.4 mph is the speed of the car
:
;
Confirm this, find the distance each traveled
5.5*15.6 = 85.8 mi
5.5*48.4 = 266.2 mi
--------------------
total dist: 352.0
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SOLUTION: Suppose that a cyclist began a 352 mi ride across a state at the western edge of the&#8203; state, at the same time that a car traveling toward it leaves the eastern end of the

SOLUTION: Suppose that a cyclist began a 352 mi ride across a state at the western edge of the state, at the same time that a car traveling toward it leaves the eastern end of the