SOLUTION: Hello can you answer these questions for me1 1. Factor x^2-3x-18 2. Factor 2y^2+8y+9y+36 3. Factor w^2-81v^2 4. Factor 5x^2+23xy+12y^2

Algebra ->  Algebra  -> Expressions-with-variables -> SOLUTION: Hello can you answer these questions for me1 1. Factor x^2-3x-18 2. Factor 2y^2+8y+9y+36 3. Factor w^2-81v^2 4. Factor 5x^2+23xy+12y^2      Log On

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Question 110760: Hello can you answer these questions for me1
1. Factor
x^2-3x-18
2. Factor
2y^2+8y+9y+36
3. Factor
w^2-81v^2
4. Factor
5x^2+23xy+12y^2

Found 2 solutions by scott8148, jim_thompson5910:
Answer by scott8148(5895) About Me  (Show Source):
You can put this solution on YOUR website!
1. (x-6)(x+3)

2. (2y+9)(y+4)

3. difference of two perfect squares factors into sum and difference of square roots ... (w+9v)(w-9v)

4. (5x+3y)(x+4y)

Answer by jim_thompson5910(21685) About Me  (Show Source):
You can put this solution on YOUR website!
#1
"Factor x^2-3x-18"

Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)
In order to factor x%5E2-3%2Ax-18, first multiply the leading coefficient 1 and the last term -18 to get -18. Now we need to ask ourselves: What two numbers multiply to -18 and add to -3? Lets find out by listing all of the possible factors of -18


Factors:

1,2,3,6,9,18,

-1,-2,-3,-6,-9,-18, List the negative factors as well. This will allow us to find all possible combinations

These factors pair up to multiply to -18.

(-1)*(18)=-18

(-2)*(9)=-18

(-3)*(6)=-18

Now which of these pairs add to -3? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -3

||||||
First Number|Second Number|Sum
1|-18|1+(-18)=-17
2|-9|2+(-9)=-7
3|-6|3+(-6)=-3
-1|18|(-1)+18=17
-2|9|(-2)+9=7
-3|6|(-3)+6=3


We can see from the table that 3 and -6 add to -3. So the two numbers that multiply to -18 and add to -3 are: 3 and -6

So the original quadratic


x%5E2-3%2Ax-18


breaks down to this (just replace -3%2Ax with the two numbers that multiply to -18 and add to -3, which are: 3 and -6)


x%5E2%2Bhighlight%283x-6x%29-18 Replace -3%2Ax with 3x-6x

Group the first two terms together and the last two terms together like this:

%28x%5E2%2B3x%29%2B%28-6x-18%29

Factor a 1x out of the first group and factor a -6 out of the second group.


1x%28x%2B3%29%2B-6%28x%2B3%29


Now since we have a common term x%2B3 we can combine the two terms.


%28x-6%29%28x%2B3%29 Combine like terms.
==============================================================================

Answer:


So the quadratic x%5E2-3%2Ax-18 factors to %28x-6%29%28x%2B3%29




Notice how %28x-6%29%28x%2B3%29 foils back to our original problem x%5E2-3%2Ax-18. This verifies our answer.






#2
"Factor 2y^2+8y+9y+36"

2y%5E2%2B8y%2B9y%2B36 Start with the given expression

%282y%5E2%2B8y%29%2B%289y%2B36%29 Group like terms


2y%28y%2B4%29%2B9%28y%2B4%29 Factor out the GCF of 2y out of the first group. Factor out the GCF of 9 out of the second group


%282y%2B9%29%28y%2B4%29 Since we have a common term of y%2B4, we can combine like terms

So 2y%5E2%2B8y%2B9y%2B36 factors to %282y%2B9%29%28y%2B4%29






#3
"Factor w^2-81v^2"

w%5E2-81v%5E2 Start with the given expression

Let A%5E2=w%5E2 and B%5E2=81v%5E2. So we get this:

w%5E2-81v%5E2=A%5E2-B%5E2

Since A%5E2=w%5E2, A can be solved for:
sqrt%28A%5E2%29=sqrt%28w%5E2%29 Take the square root of both sides

A=w

Since B%5E2=81v%5E2, B can be solved for:
sqrt%28B%5E2%29=sqrt%2881v%5E2%29 Take the square root of both sides

B=9v

Since we have a difference of squares, we can factor it like this:

A%5E2-B%5E2=%28A%2BB%29%28A-B%29



Now replace A and B
w%5E2-81v%5E2=%28w%2B9v%29%28w-9v%29 Plug in A=w and B=9v

So the expression

w%5E2-81v%5E2

factors to

%28w%2B9v%29%28w-9v%29

Notice that if you foil the factored expression, you get the original expression. This verifies our answer.





#4
"Factor 5x^2+23xy+12y^2"


Looking at 5x%5E2%2B7xy-12y%5E2 we can see that the first term is 5x%5E2 and the last term is -12y%5E2 where the coefficients are 5 and -12 respectively.

Now multiply the first coefficient 5 and the last coefficient -12 to get -60. Now what two numbers multiply to -60 and add to 7? Let's list all of the factors of -60:



Factors of -60:
1,2,3,4,5,6,10,12,15,20,30,60

-1,-2,-3,-4,-5,-6,-10,-12,-15,-20,-30,-60 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to -60
(1)*(-60)
(2)*(-30)
(3)*(-20)
(4)*(-15)
(5)*(-12)
(6)*(-10)
(-1)*(60)
(-2)*(30)
(-3)*(20)
(-4)*(15)
(-5)*(12)
(-6)*(10)

note: remember, the product of a negative and a positive number is a negative number


Now which of these pairs add to 7? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 7

First NumberSecond NumberSum
1-601+(-60)=-59
2-302+(-30)=-28
3-203+(-20)=-17
4-154+(-15)=-11
5-125+(-12)=-7
6-106+(-10)=-4
-160-1+60=59
-230-2+30=28
-320-3+20=17
-415-4+15=11
-512-5+12=7
-610-6+10=4



From this list we can see that -5 and 12 add up to 7 and multiply to -60


Now looking at the expression 5x%5E2%2B7xy-12y%5E2, replace 7xy with -5xy%2B12xy (notice -5xy%2B12xy adds up to 7xy. So it is equivalent to 7xy)

5x%5E2%2Bhighlight%28-5xy%2B12xy%29%2B-12y%5E2


Now let's factor 5x%5E2-5xy%2B12xy-12y%5E2 by grouping:


%285x%5E2-5xy%29%2B%2812xy-12y%5E2%29 Group like terms


5x%28x-y%29%2B12y%28x-y%29 Factor out the GCF of 5x out of the first group. Factor out the GCF of 12y out of the second group


%285x%2B12y%29%28x-y%29 Since we have a common term of x-y, we can combine like terms

So 5x%5E2-5xy%2B12xy-12y%5E2 factors to %285x%2B12y%29%28x-y%29

So this also means that 5x%5E2%2B7xy-12y%5E2 factors to %285x%2B12y%29%28x-y%29 (since 5x%5E2%2B7xy-12y%5E2 is equivalent to 5x%5E2-5xy%2B12xy-12y%5E2)