SOLUTION: solve the system by additio or substitution
3x+6y=0
x= 2/3
I have no idea how to work this problem with a fraction. Please help.
Algebra.Com
Question 109890: solve the system by additio or substitution
3x+6y=0
x= 2/3
I have no idea how to work this problem with a fraction. Please help.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
3x+6y=0
x= 2/3
:
Just substitute 2/3 for x in the 1st equation, and find y
:
3() + 6y =0
:
The 3's cancel and you have;
2 + 6y = 0
6y = -2
y =
y =
:
:
Check solution in the original equation:
3() + 6() = 0
2 - 2 = 0
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