SOLUTION: A, B, C and D are positive integers such that A^2 + 3B^2 + 3C^2 + 5D^5 = 1002. What is the value of A x B x C x D? Find all possible solutions.

Question 1087519: A, B, C and D are positive integers such that A^2 + 3B^2 + 3C^2 + 5D^5 = 1002. What is the value of A x B x C x D? Find all possible solutions.
Answer by ikleyn(52777) (Show Source): You can put this solution on YOUR website!
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A	B	C	D		A^2+3*B^2+3*C^2+5D^5		A*B*C*D
29	6	4	1		1002	    	                696
29	4	6	1		1002		                696
19	14	4	1		1002		                1064
19	4	14	1		1002		                1064
11	16	6	1		1002		                1056
11	6	16	1		1002		                1056

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