SOLUTION: 600 liters of 50% alcohol solution was diluted to make a 40% alcohol solution. How many liters of the 50% solution needed to be replaced by pure water in order to bring the alcohol
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Question 1080914: 600 liters of 50% alcohol solution was diluted to make a 40% alcohol solution. How many liters of the 50% solution needed to be replaced by pure water in order to bring the alcohol concentration down to 40%
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
Let n be the amount of pure water to be added. Then:
.5(600)=.4(600+n)
300=240+.4n
60=.4n
n=150 liters of pure water needs to be added. ☺☺☺☺
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