SOLUTION: solve the system by substitution:
4x-4y=0
y=2x-5
Algebra.Com
Question 107810: solve the system by substitution:
4x-4y=0
y=2x-5
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
Y=2X-5
4X-4(2X-5)=0
4X-8X+20=0
-4X=-20
X=-20/-4
X=5 ANSWER.
Y=2*5-5
Y=10-5
Y=5
PROOF
4*5-4*5=0
20-20=0
0=0
RELATED QUESTIONS
solve the system by substitution:
4x-4y=0... (answered by scott8148)
Solve the system by substitution.
4x – 4y = –4
y = 2x + 0
(answered by rapaljer)
Solve the system by substitution.
-x-y-z=-8
-4x+4y+5z=7... (answered by ewatrrr)
Solve the system by substitution
-x-y-z=-8
-4x+4y+5z=7... (answered by Alan3354)
Solve the system of linear equations by substitution. Check your solution.
4x + 2y =... (answered by addingup)
Solve the system by substitution
4x+3y=30... (answered by rapaljer)
Solve the system by substitution:
2x+2y=0... (answered by tutorcecilia)
Solve the system by substitution.
2x + 2y = 0
y = 4x +... (answered by checkley71)
Solve the system by substitution
2x+2y=0... (answered by jim_thompson5910)