Question 1076243: The difference of two numbers is 44 and the sum of their squares is 106106. Find the numbers. Found 3 solutions by ankor@dixie-net.com, ikleyn, Alan3354:Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website! The difference of two numbers is 44
a - b = 44
a = (b+44)
and the sum of their squares is 106106.
a^2 + b^2 = 106106
replace a with (b+44)
(b+44)^2 + b^2 = 106106.
FOIL
b^2 + 88b + 1936 + b^2 = 106106
2b^2 + 88b + 1936 - 106106 = 0
2b^2 + 88b - 104170 = 0
simplify, divide by 2
b^2 + 44b - 52085 = 0
Using the quadratic formula I got a positive, awkward solution of:
b = 207.279306
then
a = 251.279306
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See if this checks out on you calc, enter: 251.279306^2 + 207.279306^2