SOLUTION: Divide the following fractions. 16x/4x^2-16 divided by 4x-24/x^2- 4x -12

Question 107084: Divide the following fractions.
16x/4x^2-16 divided by 4x-24/x^2- 4x -12

Answer by Annabelle1(69) (Show Source): You can put this solution on YOUR website!
facrorise all components of this question first.
4x^2-16 =4(x^2-4)= 4(x-2)(x+2) (differnce of 2 squares)
4x-24=4(x-6)
x^2-4x-12= (x-6)(x+2)
when we divide two fractions, we can flip the second one up-side-down and multiply
so we have:
multiplied by
which is
a lot of terms now cancel like the 16, x-6, x+2
we are left with
RELATED QUESTIONS
Divide x^2-4x+16 divided by... (answered by jsmallt9)

Divide the fractions: [(x^2-2x)/4x] � [(6x-12)/8] (answered by Earlsdon)

please help me solve the equations by factorizing the following poly-nominal fully... (answered by solver91311)

help divide these fractions 4x^2/x^2 - 25 divided 2x/x^2 + 2x -... (answered by ankor@dixie-net.com)

4x^2+16x+16 solve for... (answered by drumwrrv)

Please simplify the expression. {{{16x^2 over 8x divided by 4x^2 over... (answered by ankor@dixie-net.com)

4x^2+16x+12=0 (answered by Theo)

(x^3 + 6x^2 + 4x - 16) divided by (x+4)=... (answered by brownef8)

How do I divide? Do I cancell out first? fraction 1: 12-4x/x^2-1 divided by fraction... (answered by monika_p)