SOLUTION: find all values of x such that y=0 y = 5[x-(6-x)]-9(x+1)

Question 1067307: find all values of x such that y=0
y = 5[x-(6-x)]-9(x+1)
Answer by Edwin McCravy(20063) (Show Source): You can put this solution on YOUR website!

Here's one exactly like it with the numbers changed.
Follow it step by step with the numbers in your equation

y = 4[x-(5-x)]-7(x+1)

Replace y by 0

0 = 4[x-(5-x)]-7(x+1)

Remove the parentheses in -(5-x) as -5+x
and replace -(5-x) by -5+x

0 = 4[x-5+x]-7(x+1)

Replace x-5+x by 2x-5

0 = 4[2x-5]-7(x+1) 

Use the distributive principle to replace
4[2x-5] by 8x-20

0 = 8x-20-7(x+1)

Use the distributive principle to replace
-7(x+1) by -7x-7

0 = 8x-20-7x-7

Combine like terms and replace the right side by x-29

0 = x-27

Add 27 to both sides

27 = x

Now do yours by following the same exact steps.

Edwin

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