SOLUTION: Find three consecutive integers such that twice the first is equal to 17 more than the largest. (only an algebraic solution will be excepted) How do I solve this? Ple

SOLUTION: Find three consecutive integers such that twice the first is equal to 17 more than the largest. (only an algebraic solution will be excepted) How do I solve this? Ple

Algebra.Com

Question 1029682: Find three consecutive integers
such that twice the first is equal
to 17 more than the largest.
(only an algebraic solution will
be excepted)
How do I solve this?
Please help, and thank you!!
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Call the integers, x, x+1, and x+2.
Then we can write
2x = 17 + x+2
2x = x + 19
x = 19
x+1 = 20
x+2 = 21

RELATED QUESTIONS
Find three consecutive even integers such that twice the largest is equal to two more... (answered by namra)

set up an equation and solve. find three even consecutive integers such that twice the (answered by rothauserc)

find three consecutive integers such that twice the smallest is twelve more than the... (answered by wilft1)

Find three consecutive integers such that twice the smallest is 12 more than the... (answered by CubeyThePenguin)

Find three consecutive integers such that twice the smallest is 12 more than the... (answered by CubeyThePenguin)

Find three consecutive positive odd integers such that the product of the first and third (answered by ewatrrr)

1) find three positive consecutive odd integers such that the largest decreased by twice... (answered by stanbon)

Fine four consecutive odd integers such that the sum of the first three is five more than (answered by Alan3354)

Find three consecutive integers such that the sum of twice the first and 4 times the... (answered by richwmiller)