Please help me solve the following for x, y, and z. and please show the work.
3x+2y+z=8
2x-3y+2z=-16
x+4y-z=20
3x + 2y + z = 8 ------ eq (i)
2x – 3y + 2z = - 16 ------ eq (ii)
x + 4y – z = 20 ------ eq (iii)
4x + 6y = 28 ---------- Adding eqs (i) & (iii) ------- eq (iv)
2x + 8y – 2z = 40 ----- Multiplying eq (iii) by 2 ---- eq (v)
4x + 5y = 24 ---------- Adding eqs (v) & (ii) -------- eq (vi)
-------- Subtracting eq (vi) from eq (iv)
4x + 6(4) = 28 -------- Substituting 4 for y in eq (iv)
4x + 24 = 28
4x = 4
x = , or
1 + 4(4) – z = 20 --------- Substituting 1 for x and 4 for y in eq (iii)
1 + 16 – z = 20
17 – z = 20
- z = 20 – 17
z = , or