SOLUTION: a) Perform the indicated operation. Reduce each answer to lowest terms. Frist one: 4/3n + 2/n+1 + 2/n^2+n B)Simplify each complex fraction. Reduce each answer to lowe

Question 102755: a) Perform the indicated operation. Reduce each answer to lowest terms.
Frist one: 4/3n + 2/n+1 + 2/n^2+n

B)Simplify each complex fraction. Reduce each answer to lowest terms.

Frist one: 1/3 + 1/y / y/3-3/y

Second one: ab+b^2/4ab^5 / a+b/6a^2b^4

c)Solve each equation:

Frist one: 2+4/2 = a+4/a

Second one: 3/x-2 - 5/x+3 = 1/x^2+x-6

Can somoene please help me with the above. thank you so much for any help you can provide me with
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Reduce each answer to lowest terms.
Frist one: 4/3n + 2/n+1 + 2/n^2+n
Least Common Denominator: 3n(n+1)
Rewrite each fraction with the lcd as its denominator:
[4(n+1)/lcd] + [2(3n)/lcd] + [2*3/lcd]
Combine the numerators over the lcd:
[4n+4 + 6n + 6]/lcd
Simplify:
[10n+10]/[3n(n+1)]
Factor:
[10(n+1)]/[3n(n+1)]
Cancel the (n+1) to get
10/3n
====================
B)Simplify each complex fraction. Reduce each answer to lowest terms.
First one: [1/3 + 1/y] / [y/3-3/y
[(y+3)/3y] / [y^2-9/3y]
Invert the denominator and multiply:
[(y+3)/3y] * [3y/(y^2-9)]
Factor and cancel to get:
1/(y-3)
================

Second one: [(ab+b^2)/4ab^5] / [(a+b)/6a^2b^4]
Invert the denominator and multiply:
[(ab+b^2)/4ab^5] * [6a^2b^4/(a+b)]
Factor and cancel:
[a/4ab^4]
[a*3a/2]
(3/2)a^2
========================
Comment:
See if you can do the last two.
Cheers,
Stan H.
c)Solve each equation:
First one: 2+4/2 = a+4/a

Second one: 3/x-2 - 5/x+3 = 1/x^2+x-6

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