SOLUTION: Factor completely: b^3m^3-14b^2m^2+49bm Here are my options, which do not help me at all:( a) bm9b^2m^2-14bm+49) b) bm(bm-7)(bm+7) c) m(b^3m-7b^2) d) bm(bm-7)^2 Plea

Question 102704: Factor completely:
b^3m^3-14b^2m^2+49bm
Here are my options, which do not help me at all:(
a) bm9b^2m^2-14bm+49)
b) bm(bm-7)(bm+7)
c) m(b^3m-7b^2)
d) bm(bm-7)^2
Please help me understand this a little better. Thank you, thank you.
Answer by elima(1433) (Show Source): You can put this solution on YOUR website!

First you will factor out any commons, they each have bm, so we will factor that out;

Now factor the equation;
bm(bm-7)(bm-7)

Hope this helps
:)
RELATED QUESTIONS
So theres a line A------------M-------------B and M is the midpoint AM is x^2-6 BM is (answered by MathLover1)

If a^2 - am + bm + b^2 , what is m in terms of a and b? A) b - a B) a - b C) a + b... (answered by sofiyac)

Problem is: {{{(8)/(2m+1)-(1)/(m-2)=(5)/(2m+1)}}} I've tried several ways, but can't... (answered by Alan3354,richwmiller)

which property of exponents must be used first to solve this expression? (xy2)1/3 a.... (answered by ewatrrr)

The directions say: Solve the equation. Check your solution. {{{2m/(m+4) = 3/(m-1)}}} (answered by stanbon,josmiceli)

(3m / 2m^2 + 7m - 15) + (6 / 2m^2 - 3m) + (2m + 3 / 2m^2 + 17m +... (answered by KMST)

2m^3+3m^2-32m-48 polynomial factoring... (answered by jim_thompson5910)

(4m-3m)(2m*2-3m+7) (answered by Math-Genius)

Factor trinomial... (answered by swincher4391)