SOLUTION: factor: (2x+5)^2-(2x+5)-12 I used the substitution method: let u=2x+5 u^2-u-12 (u-4)(u+3) {(2x+5)-4}{2x+5)+3} (2x+5-4)(2x+5+3) (2x+1)(2x+8) 2(2x+1)(x+4) Is this co

Algebra.Com
Question 102425: factor: (2x+5)^2-(2x+5)-12
I used the substitution method:
let u=2x+5
u^2-u-12
(u-4)(u+3)
{(2x+5)-4}{2x+5)+3}
(2x+5-4)(2x+5+3)
(2x+1)(2x+8)
2(2x+1)(x+4)
Is this correct?

Found 2 solutions by stanbon, edjones:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
factor: (2x+5)^2-(2x+5)-12
I used the substitution method:
let u=2x+5
u^2-u-12
(u-4)(u+3)
{(2x+5)-4}{2x+5)+3}
(2x+5-4)(2x+5+3)
(2x+1)(2x+8)
2(2x+1)(x+4)
Correct
===============
Cheers,
Stan H.

Answer by edjones(8007)   (Show Source): You can put this solution on YOUR website!
yes
Very good!
Ed

RELATED QUESTIONS

how would u solve 5/2x - 4/x= -3... (answered by nyc_function)
How do u solve... (answered by jim_thompson5910)
Can u please factor this:... (answered by tutorcecilia)
Solve:- 3/2x-3+4/3-2x-5/8x-12=1 I am confused can u pls help me urgently.... (answered by jim_thompson5910)
{{{((u^(3/4))(u^(1/3)))/((u^(2/3))(u^(5/6)))}}}=u^(a/b) where a=? and... (answered by venugopalramana)
CAN U SOLVE... (answered by Cromlix)
3(2x-2)-5=2x+4+x (answered by rfer)
How would I factor this? {{{12(4x-1)^3(2x+5)^9 +3(4x-1)^4(2x+5)^8}}} My attempt:... (answered by jim_thompson5910)
4 -(2x-3)>12... (answered by mananth)