Since x is already eliminated from the
2nd equation, we will eliminate x
from the 1st and 3rd by multiplying the
1st equation through by -1 and adding
it term by term to the 3rd equation like this:

-2x+3y-3z=3
 2x+3y+4z=9
------------
    6y+ z=12

Now we take that with the 2nd original equation
and we have a system of 2 equations in 2 unknowns:



However we can see that if 6y+z=8, then 6y+z cannot
equal 12, so there is no solution.

This is an inconsistent system of equations.

Edwin