SOLUTION: The perimeter of a rectangle is 52m. The length is 2m longer than 3 times the width. Find the length and width.

Question 1014615: The perimeter of a rectangle is 52m. The length is 2m longer than 3 times the width. Find the length and width.
Found 2 solutions by fractalier, solver91311:
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
The perimeter P = 2L + 2W = 52. We also have
L = 3W + 2
Substituting we have
2(3W + 2) + 2W = 52
6W + 4 + 2W = 52
8W = 48
W = 6m
L = 3(6) + 2 = 20m
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

Let represent the width and represent the length. Since :

,

In other words:

If the length is units more than times the width, then:

Hence:

Substitute your given values for , , and and then solve for . Finally, calculate

John

My calculator said it, I believe it, that settles it

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