SOLUTION: Jason has 46 total coins with a mixture of dimes and quarters. The total value of his coins is $6.55. How many dimes and how many quarters does Jason have?

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Question 1013548: Jason has 46 total coins with a mixture of dimes and quarters. The total value of his coins is $6.55. How many dimes and how many quarters does Jason have?
Found 2 solutions by ikleyn, Alan3354:
Answer by ikleyn(52802)   (Show Source): You can put this solution on YOUR website!
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Jason has 46 total coins with a mixture of dimes and quarters. The total value of his coins is $6.55.
How many dimes and how many quarters does Jason have?
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Let d = # of dimes and q = # of quarters Jason has.

Then you have this system of two equations in two unknowns d and q:

  d +   q =  46,    (1)
10d + 25q = 655.    (2)

From (1), express d = 46 - q and substitute it into (2). In this way, you get a single equation for q:

10*(46 - q) + 25q = 655,

460 - 10q + 25q = 655,

15q = 655 -460,

15q = 195,

q =  = 13.

Answer. Jason has 13 quarters and 46 - 13 = 33 dimes.


Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Jason has 46 total coins with a mixture of dimes and quarters. The total value of his coins is $6.55. How many dimes and how many quarters does Jason have?
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Here's another method.
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46 dimes = $4.60
Each dime replaced by a quarter adds 15 cents.
655 - 460 = 195
195/15 = 13 replacements.
--> 13 quarters & 33 dimes
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