SOLUTION: Please help me solve this :
In an geometric progression , b1=3 and b2=6
Solve b2015
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Question 1012864: Please help me solve this :
In an geometric progression , b1=3 and b2=6
Solve b2015
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Please help me solve this :
In an geometric progression , b1=3 and b2=6
--------
a = 3
ar = 6
---
ar/a = 6/3
r = 2
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Solve b2015 = ar^(2014) = 3*2^2014
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Cheers,
Stan H.
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