SOLUTION: find the length of the shortest side of a triangle whose perimeter is 66 and the sides are marked as x+5, 3X-1 AND 4X-2 what is the shortest side
Question 1012193: find the length of the shortest side of a triangle whose perimeter is 66 and the sides are marked as x+5, 3X-1 AND 4X-2 what is the shortest side Found 2 solutions by macston, ikleyn:Answer by macston(5194) (Show Source): You can put this solution on YOUR website! .
Perimeter is the sum of the sides.
.
(x+5)+(3x-1)+(4x-2)=66
8x+2=66
8x=64
x=8
.
x+5=8+5=13
The x+5 side is 13
.
3x-1=3(8)-1=24-1=23
The 3x-1 side is 23
.
4x-2=4(8)-2=32-2=30
The 4x-2 side is 30
.
ANSWER: The shortest side is x+5=13
.
Answer by ikleyn(52798) (Show Source): You can put this solution on YOUR website! .
find the length of the shortest side of a triangle whose perimeter is 66 and the sides are marked as x+5, 3X-1 AND 4X-2 what is the shortest side
---------------------------------------------------------------------
Your equation is
(x+5) + (3x-1) + (4x-2) = 66.
8x + (5-1-2) = 66,
8x + 2 = 66,
8x = 66 - 2 = 64,
x = 8.
The sides of the triangle are:
side 1: x + 5 = 8+5 = 13;
side 2: 3x-1 = 3*8-1 = 23;
side 3: 4x - 2 = 4*8 - 2 = 30,
The shortest side is 13.