SOLUTION: (1+2+3+...+19)20 ----------- ----------- ----- = (21+22+23+...+39)40 Find 3 (n)s

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Question 1006529: (1+2+3+...+19)20
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(21+22+23+...+39)40

Find 3 (n)s

Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.
What to find ?

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Comment from student: simplify it into an expression using n
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OK. (Why do not write it from the very beginning?)

The sum in the numerator is the sum of first 19 terms of an arithmetic progression 1, 2, 3, . . . , 19

S = 1 + 2 + 3 + . . . + 19 = = = 10*19.

The sum in the numerator is the sum of first 19 terms of an arithmetic progression 21, 22, 23, . . . , 39

T = 21 + 22 + 23 + . . . + 39 = = = 30*19.

Hence, the ratio you are asking for, is

= = = .


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