# SOLUTION: The product of two consecutive positive even integers is 360. Find the integers. Let the x=first even integer. Then x+2 is the next even integer. Their product is 360: x(x+2

Algebra ->  -> SOLUTION: The product of two consecutive positive even integers is 360. Find the integers. Let the x=first even integer. Then x+2 is the next even integer. Their product is 360: x(x+2      Log On

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 Click here to see ALL problems on Expressions-with-variables Question 71187: The product of two consecutive positive even integers is 360. Find the integers. Let the x=first even integer. Then x+2 is the next even integer. Their product is 360: x(x+2)=360. You have a quadratic: x^2+2x-360=0 Factor: (x-18)(x+20)=0 x=18, x+2=20 18*20=360 The integers are 18 and 20. Found 2 solutions by elima, galactus:Answer by elima(1433)   (Show Source): You can put this solution on YOUR website!The product of two consecutive positive even integers is 360. Find the integers. let x = integer. since they are positive even integers, the next integer will be; x+2 = integer #2 equation; x(x+2)=360 +2x=360 subtract both sides by 360; +2x-360=0 factor; (x-18)(x+20)=0 x-18=0 x+20=0 x=18 x=-20 since they are even integers, they answer has to be; x=18 now plug 18 into the equation for x; 18(18+2)=360 18(20)=360 360=360 so your integers are; 18 and 20 :) Answer by galactus(183)   (Show Source):