SOLUTION: (4x to the -3) (z) divided by (2 to the -2)(y to the 4)(w to the -2) = ?
The answer is supposed to be (16w squared)(z) divided by (x cubed)(y to the 4th)
For step 1, I remove
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Question 976134: (4x to the -3) (z) divided by (2 to the -2)(y to the 4)(w to the -2) = ?
The answer is supposed to be (16w squared)(z) divided by (x cubed)(y to the 4th)
For step 1, I remove the negative exponents and get: (z)/(4x cubed) divided by (y to the 4th) / (4w squared).
For step 2, I invert the denominator and multiply the following: (z)/(4x cubed) times (4w squared / (y to the 4th).
After this I'm making an error because I'm not getting to the coefficient of 16 in the numerator and 1 in the denominator.
Thank you in advance for any help.
Helen
Found 2 solutions by Boreal, solver91311:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
4x^-3) * 4z *y^-4*w^2
One error is 4x^-3. This has to be written carefully, for (4x)^-3 is very different (1/64x^3). You want 4 in the numerator/x^3 in the den.
4x^-3 *4z because divide by 2^-2 is to divide by 1/4 or multiply by 4 /y^4
x^-3 is 1/x^3
4*4 is 16
Leave the 4 alone and recognize that dividing by 2^-2 is another 4, and your numerator will be 16.
Put them together: {16 z/x^3} * {w^2/y^4}
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
(z)}{2^{-2}y^4w^{-2}})
And you assert that this is equal to
Why did you put the factor of 4 that was in the original numerator into a denominator? There is no negative exponent on that coefficient.
^{-3})
Try it again with this fact in mind and see what happens. Write back if you are still having difficulty.
John
My calculator said it, I believe it, that settles it
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