SOLUTION: binomial squared to multiply: (6x+5)exponent2 my work: (6x+5)(6x+5)= 36xexponent2 + 30x + 30x + 25= 36xexponent2 + 60xexponent2 + 25= 96xexponent4 + 25

Algebra.Com
Question 93711This question is from textbook Beginning Algebra
: binomial squared to multiply:
(6x+5)exponent2
my work: (6x+5)(6x+5)=
36xexponent2 + 30x + 30x + 25=
36xexponent2 + 60xexponent2 + 25=
96xexponent4 + 25
This question is from textbook Beginning Algebra

Found 2 solutions by Earlsdon, jayanthihemkos@yahoo.com:
Answer by Earlsdon(6294)   (Show Source): You can put this solution on YOUR website!
Er...not quite!
Your first step was fine.
but...
not so...

Answer by jayanthihemkos@yahoo.com(87)   (Show Source): You can put this solution on YOUR website!
binomial squared to multiply:
(6x+5)exponent2

(6x + 5)^2
==> (6x + 5)(6x + 5)
==> 36x^2 +30x + 30x +25
==> 36x^2 + 60x +25 (30x + 30x = 60x , It should be added not multiplied)

RELATED QUESTIONS

30x^2y^5/-6x^8y^-3 (answered by Tatiana_Stebko)
Hello, I've been trying to solve this problem but am stuck. Solve by Substitution... (answered by Alan3354)
30x^2 y^5 / -6x^8 y^-3 (answered by ReadingBoosters)
6x+5=x+25 (answered by rfer)
6x^2+30x+36 (answered by MathLover1)
-6x^2 +30x... (answered by Alan3354)
6x^5-11x^4+30x^3 Thank you very much for your help, I need to factor... (answered by jim_thompson5910)
help solve the following: factor completely... (answered by Earlsdon)
If the polynomial p(x) = (x^5 - 6x + 7)^2019 - (x^5 - 6x + 9)^2020 + 5x^5 - 30x + 50 is... (answered by ikleyn)