SOLUTION: What is (4x^9) (6x^4)? I am sorry I don't know if it is considered complicated or not. I have tried multiplying the 4 and the 6 and then adding the exponents to get 24x^13 but I do
Algebra.Com
Question 933995: What is (4x^9) (6x^4)? I am sorry I don't know if it is considered complicated or not. I have tried multiplying the 4 and the 6 and then adding the exponents to get 24x^13 but I don't know if that is right or not. Please help me! And also thank you so much for your help, I really appreciate it.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
(4x^9)*(6x^4) = 24x^13, just like you said
RELATED QUESTIONS
Hi,
Factor the polynomial completely and find all its zeros (real and complex).... (answered by nerdybill)
This particular expression is... complicated. The original problem is... (answered by edjones)
I am stumped on this problem, its kind of long so bear with me.
The problem is about the (answered by stanbon)
I have a question about quadratic equation. I know if you need to square a negative... (answered by ankor@dixie-net.com,KMST)
I need to write in standard form and determine the values of a, b, and c, for question #4 (answered by checkley75)
Need help with the basics of logarithm.
5log 7a + 20b
I don't know how to format... (answered by ikleyn)
I have tried to solve this problem but when I check it I'm wrong! I'm stumped and don't... (answered by ReadingBoosters,stanbon)
I am trying to solve an equation with fractions. This is the problem
2x over x^2+6x+8 (answered by stanbon)
{{{ (t^2-1)/(t^2-4) }}} + {{{ (9t+9)/(4t+12) }}} * {{{ (2-t)/(t^2+2t-3) }}}
The back... (answered by Alan3354,greenestamps,MathTherapy)