SOLUTION: (2^10)(2^2)/2^9 (it's suppose to be two to the tenth times two to the second divided by two to the ninth) The answer I got was 8. I used the rule X^7*x^4=X^11 for the top

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Question 897102: (2^10)(2^2)/2^9
(it's suppose to be two to the tenth times two to the second divided by two to the ninth)
The answer I got was 8.
I used the rule X^7*x^4=X^11 for the top and the rule that when dividing with the same base you subtract. coming up with 2^3=8

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
Given:










Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

(2^10)(2^2)/2^9
(it's suppose to be two to the tenth times two to the second divided by two to the ninth)
The answer I got was 8.
I used the rule X^7*x^4=X^11 for the top and the rule that when dividing with the same base you subtract. coming up with 2^3=8

You are correct!! Good job!!
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