SOLUTION: What is the area of a rectangle with the length of {{{6a^2b}}} and a width of {{{3ab}}}?
Algebra.Com
Question 857554: What is the area of a rectangle with the length of and a width of ?
Answer by ben720(159) (Show Source): You can put this solution on YOUR website!
Area = Length times Width
Let A=area
Reorder factors
Extend exponents, multiply 6&3
Combine like terms. a*a*a = a^3, b*b = b^2, as there are 3 a's and 2 b's
The area of the rectangle is
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