SOLUTION: If y = 2^-x, find x if y = 0.0625

SOLUTION: If y = 2^-x, find x if y = 0.0625

Algebra.Com

Question 794830: If y = 2^-x, find x if y = 0.0625
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
0.0625 = 2^-x
log 0.0625 = -x log 2
log 0.0625/log 2 = -x
-4 = -x
x = 4
Hope this helps.
:-)
RELATED QUESTIONS
If x^2 + 3xy + y^2 = 45 and xy - y^2 = 0 find x and... (answered by solver91311)

how to you put {{{ (x^2/.0625)+(y+3)^2/.25=1 }}} into a y= form?(for a calculator) the... (answered by scott8148)

If x > 0 and y> 0 and x^2 - y^2 = 2xy, find the exact value of... (answered by ikleyn)

Solve if possible 3x+y+2= 0 2 x-y+2=0... (answered by ewatrrr)

Y=-16 find y if x is 0. Find y if x is... (answered by Alan3354,fractalier)

y=-16 find y,if x is... (answered by Alan3354)

If x+ 2y = 0 x -2y = 2 then (x,y) = ? (answered by josgarithmetic)

if y=e^-x^2 then y''(0)... (answered by mccravyedwin)

Find the exact value if 0 < x < pi/2 and 0 < y < pi/2 ; sin(x+y) if sin(x) = 3/5 and... (answered by fractalier)