SOLUTION: Can someone help me with this one?
I hope I write this out right...
(-3*10^-3) (2*10^2)=
I think I have some of it. I get to -6*1-^-5= (and then I am lost - if that is even
Algebra.Com
Question 748714: Can someone help me with this one?
I hope I write this out right...
(-3*10^-3) (2*10^2)=
I think I have some of it. I get to -6*1-^-5= (and then I am lost - if that is even right) Can someone show me how to do this. My text book is useless in explanations. Thanks!
Found 2 solutions by stanbon, rothauserc:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(-3*10^-3) (2*10^2)
--------
= -3*2*10^-3*10^2
--------
= -6*10^-1
----
= -6/10
----
= -0.6
============
Cheers,
Stan H.
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Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
we are asked to evaluate
(-3*10^-3) (2*10^2)= (-3/10^3) * (2*10^2) note that 10^-3 = 1/10^3
= (-3/10) * (2) cancel 10^2 from numerator and denominator
= -6/10
= -3/5
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