SOLUTION: I'm stumped 4(y-1)=-2(3+y)

SOLUTION: I'm stumped 4(y-1)=-2(3+y)

Algebra.Com

Question 722112: I'm stumped 4(y-1)=-2(3+y)

Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
4(y-1)=-2(3+y)

4y-4 = -6-2y
6y=-2
y=-2/6
y=-1/3
RELATED QUESTIONS
Can you help solve: (3x+3y+3)/9x / (x^2+2xy+y^2-1)/(x^4+x^2) I know I can... (answered by checkley77)

totally stumped on how to solve this problem: {{{ (y-1)/(y^2-3y-4)... (answered by Edwin McCravy,mananth)

parallel and perpendicular lines i need to put my answer into slope - intercept form,y=... (answered by MathLover1,lwsshak3)

If {{{ log(x, y^4) = m^3 }}} and {{{ log(y, x) = 4 / m^2 }}}, prove that m = 1. (answered by Solver92311,MathLover1,greenestamps)

what is y when (2, y), (4, 5), m= 2 what is y when (-5, 3), (3,y), m= -1/2 what is y... (answered by checkley71)

I need to know the axis of symmetry for y = 4x^2 + 1/2x + 3. I already tried doing this... (answered by Alan3354,rothauserc)

(-5,3),(3,y),m=-1/2 (answered by josgarithmetic)

I'm stumped on the following problem. y/2+4=1/6 I have no clue how to start this... (answered by Alan3354)

i am working on linear equations for my test tomorrow, but I am stumped on one problem... (answered by jim_thompson5910)