SOLUTION: ok... I have tried many times to work the following problem correctly: {m^(x^3-3X)(2X)^3{m^(x^2+4)(6x^4)} please note the carrot symbol indicates an exponent. also, right aft

Question 69501: ok... I have tried many times to work the following problem correctly: {m^(x^3-3X)(2X)^3{m^(x^2+4)(6x^4)}
please note the carrot symbol indicates an exponent.
also, right after the FIRST m , there is a carrot. This is there to let you know the things in parentheses are above the "M"
Thanks. Any help would be appreciated!!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
{m^(x^3-3X) (2X)^3 {m^(x^2+4)(6x^4)}
I have to assume where the 1st bracket ends.
I have to assume the (2x)^3 is NOT part of the 1st exponent.
I have to assume the (6x^4) is NOT part of the 2nd exponent.
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IF all those assumptions are correct the problem becomes:
[(m^(x^3-3x)) * (m^(x^2+4))] [((2x)^3) * ((6x^4))]
=[m^(x^3+x^2-3x+4)] [(8x^3)(6x^4)]
=[m^(x^3+x^2-3x+4)] [48x^7]
----------------------------
If that is not the answer it's because one or more or
my assumptions was wrong.
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Cheers,
Stan H.

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