SOLUTION: 81x^4-16y^4 (p+8q)^2-10(p+8q)+25

Question 68560: 81x^4-16y^4
(p+8q)^2-10(p+8q)+25
Found 2 solutions by funmath, stanbon:
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
81x^4-16y^4
These are easier if you remember that to factor the difference of perfect squares:

a=9x^2 and b=4y^2

The sum of perfect squares is prime, but the second set of parentheses is the difference of perfect squares and can be factored:
a=3x and b=2y

:
(p+8q)^2-10(p+8q)+25
These are easier if you remember that a perfect square trinomial can be factored:

a=(p+8q) and b=5

:
Happy Calculating!!!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
81x^4-16y^4
Rewrite as: (3x)^4 -(2y)^4
Factor as: [(3x)^2 + (2y)^2][(3y+2y)][(3x)-(2x)]
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Cheers,
Stan H.
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