SOLUTION: What is an equation of the line that is perpendicular to 2y+2= -7/4(x-7) and contains (-2,-3)? thanks if you can help

Question 682156: What is an equation of the line that is perpendicular to 2y+2= -7/4(x-7) and contains (-2,-3)?
thanks if you can help
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
What is an equation of the line that is perpendicular to 2y+2= -7/4(x-7) and contains (-2,-3)?
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Find the slope of the given equation:
2y = (-7/4)x + (49/4) - 2
y = (-7/8)x + some constant
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Therefore its slope is -7/8
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Any line perpendicular to it must have slope = 8/7
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Your Equation:
Form: y = mx + b
You know m = 8/7 and y = -3 when x = -2
Solve for "b":
-3 = (8/7)(-2)+ b
-3 = -16/7 + b
b = (-21/7)+(16/7)
b = -5/7
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Equation:
y = (8/7)x - (5/7)
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Cheers,
Stan H.
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