SOLUTION: a to the six minus B to the sixth

SOLUTION: a to the six minus B to the sixth

Algebra.Com

Question 666189: a to the six minus B to the sixth
Answer by swincher4391(1107) (Show Source): You can put this solution on YOUR website!
a^6 - b^6 = (a^3)^2 - (b^3)^2 = (a^3-b^3)(a^3+b^3) = [(a-b)(a^2+ab+b^2)][(a+b)(a^2-ab+b^2)]
Putting it together a little more nicely we get:
(a+b)(a-b)(a�+ab+b�)(a�-ab+b�)

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