SOLUTION: in my text book it is written that the expression is a linear polynomial with degree 1 but my doubt is that how is this possible according to my doubt is not a linear polyn

Question 665005: in my text book it is written that the expression is a linear polynomial with degree 1
but my doubt is that how is this possible
according to my doubt is not a linear polynomial as this expression is having a sqrt in the variable. if an expression is having sqrt then its power will be negative. according to the the definition of polynomials there shoud'nt be a negative integral exponent for variables. so is not a polynomial.if it is not a polynomial we cant call it as a linear polynomial.this is my statement
then how is that in the book(maths grade 8 oxford) it is mentioned is a linear polynomial with degree 1. pls explain me
Answer by kevwill(135) (Show Source): You can put this solution on YOUR website!
The terms "linear polynomial" and "degree 1" are redundant. A linear polynomial is a polynomial with degree 1. The degree of the polynomial is equal to the highest degree of any term in the polynomial. With those definitions, if the highest degree of any term in the polynomial is 1, then the polynomial is itself of degree 1, and therefore linear.

Roots are NOT negative integral exponents--they are fractional exponents. In the case of a square root, the fractional exponent is , so the degree of that term of the polynomial is also . As long as there is a term in the polynomial that is degree 1 (or higher), then having another term of degree will not change the degree of the polynomial, since

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