SOLUTION: Solve x in the following exponential notation {{{9^(2x+1)=243}}}
Algebra.Com
Question 641766: Solve x in the following exponential notation
Found 3 solutions by Earlsdon, MathLover1, DrBeeee:
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Solve for x:
Find the common base.
Simplify.
The bases are equal so the exponents are equal.
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
Answer by DrBeeee(684) (Show Source): You can put this solution on YOUR website!
Since 9 = 3^2, 9^(2x+1) is
(1) LS = 3^(4x+2)
and
(2) RS = 243 = 3^5
Equating (1) and (2) we have
(3) 3^(4x+2) = 3^5,
Since the bases are equal we can equate the exponents and obtain
(4) 4x + 2 = 5 or
(5) 4x = 3 or
(6) x = 3/4
Check your answer
Is (9^(2*(3/4)+1) = 243)?
Is (9^(10/4) = 243)?
Is (9^(5/2) = 243)?
Is ((9^(1/2))^5 = 243)?
Is (3^5 = 243)?
Is (243 = 243)? Yes
Answer is x = 3/4
RELATED QUESTIONS
Solve x in the following exponential notation {{{9^(x-1) *... (answered by lwsshak3)
Solve the following exponential equations:
a) 7^x=49
b) 243 = 9^2x+1
c) 2^2x * 4^4x +8 (answered by ewatrrr,lwsshak3)
write 243 in exponential... (answered by Earlsdon)
how do write 243 in
exponential... (answered by rfer)
Find the value of x in the following equation
(1/9)^m x (27)^-1=243
(answered by Alan3354,josgarithmetic)
11. Solve the following exponential equation. Please show all of your work.... (answered by jorel1380)
solve the equation.... (answered by edjones)
find the summation notation:... (answered by josgarithmetic)
How do you solve the exponential equation in this problem?
3^x=243
(answered by jsmallt9,dabanfield)