SOLUTION: if i was to simplify dis: n^5x/n^x would i cancel out both the n's and x's and be left woth five?? how would i do {{{(n^5/n^4)/n^3}}}???

Algebra ->  Exponents -> SOLUTION: if i was to simplify dis: n^5x/n^x would i cancel out both the n's and x's and be left woth five?? how would i do {{{(n^5/n^4)/n^3}}}???      Log On


   

Question 63546This question is from textbook
: if i was to simplify dis: n^5x/n^x would i cancel out both the n's and x's and be left woth five??
how would i do %28n%5E5%2Fn%5E4%29%2Fn%5E3??? This question is from textbook

Answer by jai_kos(139) About Me  (Show Source):
You can put this solution on YOUR website!
{(n^5/n^4)/n^3} =
Here the numerator is (n^5/n^4) and denominator is n^3
First simplify the numerator, we get
numerator = n^5/n^4 = n *n *n *n*n / n*n*n*n = n
denominator = n^3
Therefore {(n^5/n^4)/n^3} = numerator / denominator = n / n ^3 = n / n* n*n
= 1/n^2