SOLUTION: 250 + 2k^3x factor each polynomial. state prime if needed.

Algebra ->  Exponents -> SOLUTION: 250 + 2k^3x factor each polynomial. state prime if needed.      Log On


   

Question 63057: 250 + 2k^3x
factor each polynomial. state prime if needed.
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
250 + 2k^3x
factor the polynomial. state prime if needed.
2(125+k^3x) <---If the x is not part of the exponent, stop here.
If x is in the exponent, you have the sum of cubes that is factored by:highlight%28a%5E3%2Bb%5E3=%28a%2Bb%29%28a%5E2-ab%2Bb%5E2%29%29
125=5^3 (so a=5) and k^(3x)=(k^x)^3 (so b=k^x)
2%285%2Bk%5Ex%29%285%5E2-5k%5Ex%2B%28k%5Ex%29%5E2%29
highlight%282%285%2Bk%5Ex%29%2825-5k%5Ex%2Bk%5E%282x%29%29%29
Happy Calculating!!!!