SOLUTION: find dy/dx
y=2 ln x+6log2^x
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Question 605340: find dy/dx
y=2 ln x+6log2^x
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
y = 2*ln(x) + 6*log(2,x)
dy/dx = d/dx( 2*ln(x) + 6*log(2,x) )
dy/dx = d/dx( 2*ln(x) ) + d/dx( 6*log(2,x) )
dy/dx = 2*d/dx( ln(x) ) + 6*d/dx( log(2,x) )
dy/dx = 2*(1/x)+ 6*d/dx( ln(x)/ln(2) )
dy/dx = 2*(1/x)+ 6*(1/ln(2))*d/dx( ln(x) )
dy/dx = 2*(1/x)+ 6*(1/ln(2))*(1/x)
dy/dx = 2/x+ 6/(x*ln(2))
So the answer is
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