SOLUTION: (1/32)^2x=64^x+1 How would I go about solving this?
Algebra.Com
Question 604106: (1/32)^2x=64^x+1 How would I go about solving this?
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Hint: rewrite 1/32 as 1/(2^5) = 2^(-5) and rewrite 64 as 2^6
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