SOLUTION: (10x^2)^-3 OVER (5xy^-3)3 TIMES (y^8 x^2)^4 OVER (xy^2)^4 if you can help me with this that would be fantastic!!
Algebra.Com
Question 58989: (10x^2)^-3 OVER (5xy^-3)3 TIMES (y^8 x^2)^4 OVER (xy^2)^4 if you can help me with this that would be fantastic!!
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
Happy Calculating!!!
RELATED QUESTIONS
9x^2-16y^2 over xy all over 3 over y-4 over x
wouldn't xy be your common... (answered by gsmani_iyer)
complex fractions
9x^2 - 16y^2 over xy all over 3 over y - 4 over... (answered by gsmani_iyer)
im doing conic sections my homework asks me to graph {{{(x-2)^2 over 4 +(y-3)^2
over 16 (answered by lwsshak3)
Can you walk me through equations like this?
(X-5 over 5)+ (x over 4)=8
(5-2X over... (answered by stanbon)
simplify: (x^4 y^-3)^-2 over... (answered by MathLover1)
How would you solve this proportion x-4 over 2 = 3 over... (answered by solver91311)
complex fractions
9x^2-16y^2 over xy over 3 over y - 4 over x
show... (answered by gsmani_iyer)
I missed the day that we went over this and my teacher didnt teach it to me well, so im... (answered by venugopalramana)
i really need some help with this equasion: x^4 over x^5 times x^ negative 2 over x.... (answered by checkley71)