SOLUTION: I cannot remember how to distribute the exponents.
The problem I am working on is
(-2z)^2 (3z^4)^2
Algebra.Com
Question 584751: I cannot remember how to distribute the exponents.
The problem I am working on is
(-2z)^2 (3z^4)^2
Found 2 solutions by stanbon, JBarnum:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(-2z)^2 (3z^4)^2
-----
= (4z^2)(9z^8)
-----
= 36z^10
============
Cheers,
Stan H.
============
Answer by JBarnum(2146) (Show Source): You can put this solution on YOUR website!
raising an exponent to a power means you multiply the exponents
.
multiplying with exponents you add exponents
RELATED QUESTIONS
I am working on this problem and cannot remember how to do it.
3(x-2)+2=2(x-4)The... (answered by digitalbeachbum)
Hello, I am supposed to simplify this expression: (x^5/2*y^2)^-1/4
without any negative (answered by Alan3354)
Am I doing this problem in the correct way: [(6x^5y^3z)*3x^2]/(2xy^2z^5)... (answered by stanbon)
Ive been stuck on this problem for almost 2 weeks now. I just cannot seem to find an... (answered by Earlsdon)
I am still very confused on how to simplify rational expressions: This is the problem I... (answered by richwmiller,josmiceli)
I have a few I am totally stuck on.
#1)2/x+3 - 2x+3/x-1 = 6x-5/x^2+2x-3
Okay... (answered by mananth)
Simplifying Complex Fractions. I know the LCD is S, but I am not sure about how to... (answered by richwmiller,edjones)
My equation is 35-7(3z-2) and I was wondering, do I distribute 7 or -7 to the... (answered by AnlytcPhil)
I am suppose to solve the following system but don't know how.
-2x+2y+3z=-7 (1)... (answered by 303795)