SOLUTION: This is an application problem. Find the rate of a hiker who walked 4 2/3 mi. In 1 1/3 hr. Use r=d/t Where r is the rate in miles per hour. d is the distance. And t is the time. I

Question 579358: This is an application problem. Find the rate of a hiker who walked 4 2/3 mi. In 1 1/3 hr. Use r=d/t Where r is the rate in miles per hour. d is the distance. And t is the time. I could'nt figure this one out. Thanks again or your help.
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
hiker walks 4 and 2/3 miles in 1 and 1/3 hours.
the basic formuls is r*t = d
from this, you can get the formula r = d/t
d is equal to 4 and 2/3 which is equivalent to 12/3 + 2/3 which is equal to 14/3.
t is equal to 1 and 1/3 which is equivalent to 3/3 and 1/3 which is equal to 4/3
formula becomes:
r = (14/3) / (4/3) which is equivalent to:
r = (14/3) * (3/4) which is equivalent to:
r = (14*3) / (3*4) which is equal to:
r = 42 / 12 which is equal to:
r = 3 and 6/12 which is equal to:
r = 3 and 1/2 miles per hour.
3 and 1/2 is equivalent to 6/2 and 1/2 which is equal to 7/2
you have:
r = 7/2
t = 4/3
d = 14/3
since rate * time = distance, you get:
7/2 * 4/3 = 14/3
this becomes:
28/6 = 14/3 which is equivalent to:
14/3 = 14/3 which is true which means that the calculation for rate was good.
the rate is 7/2 miles per hour which is equivalent to 3 and 1/2 miles per hour.
the time is 4/3 hours which is equivalent to 1 and 1/3 hours.
the distance is 14/3 hours which is equivalent to 4 and 2/3 miles.
it might be easier to see if you convert everything to decimals.
the time was given as 1 and 1/3 hours which is equivalent to 1.33333
the distance was given as 4 and 2/3 miles which is equivalent to 4.66667
the formula is r = d/t which is equal to 4.66667 / 1.33333 which becomes 3.5 miles per hour which is the same as 3 and 1/2 miles per hour.
the fractions could have been a problem.
you want to take the mixed fractions and turn them into an improper fraction.
you then need to remember that (a/b) / (c/d) is the same as (a/b) * (d/c).
that should make it easier.

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