Question 57299This question is from textbook intermediate algebra
: 5 to the -8002 power times 5 to the 7999 power over 6 to the 212th power times 6 to the -214th power. Help! This question is from textbook intermediate algebra
You can put this solution on YOUR website! 5 to the -8002 power times 5 to the 7999 power over 6 to the 212th power times 6 to the -214th power. Help!
=[5^(-8002)][(5^(7999)]/[{6^(212)}{6^-214}]
=[5^(-8002+7999)]/[6^(212-214)]
=[5^-3]/[6^-2]
=6^2/5^3
=36/125