SOLUTION: x^2=25,other than trial and error,how does one solve for x
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Algebra: Exponents and operations on exponents
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Question 54563
:
x^2=25,other than trial and error,how does one solve for x
Answer by
stanbon(48535)
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put this solution on YOUR website!
x^2=25
x^2-25=0
(x-5)(x+5)=0
x-5 = 0 or x+5 = 0
x=5 or x=-5
Cheers,
Stan H.