SOLUTION: x to the fourth power times x to the eighth power time x to the negative third power

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WHEN YOU MULTIPLY UNKNOWNS (X)OR NUMERIC VALUES (2)YOU NEED TO ADD POSITIVE EXPONENTS & SUBTRACT NEGATIVE EXPONENTS THUS THESE EXPONEBTS ARE
+4+8-3=12-3=9 SO YOU PROBLEM BECOMES
x^4x^8x^-3 or x^(12-3) or x^9
EXAMPLE USING NUMBERS 2^4*2^8^2^-3=16*256/8=512 OR 2^9=512 (NOTE ANY VALUE TO A NEGATIVE EXPONENTS IS THE RECIPRICAL [1/(2^3)]=1/8).