SOLUTION: how do I solve:
i^11 =
that is i to the 11th power is =
Algebra.Com
Question 516540: how do I solve:
i^11 =
that is i to the 11th power is =
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
Remember:
i^0 = 1
i^1 = i
i^2 = -1
i^3 = -i
i^4 = 1
.
.
.
The pattern repeats every four times. Since 11 leaves a remainder of 3 when divided by 4, then i^11 = i^3 = -i.
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