SOLUTION: the question on the homework is stated this way:
rewrite each product using exponents
1. 3*3*5*5*5
2. 2*2*7*7
3. 5*5*7*7
Algebra.Com
Question 502028: the question on the homework is stated this way:
rewrite each product using exponents
1. 3*3*5*5*5
2. 2*2*7*7
3. 5*5*7*7
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
rewrite each product using exponents
1. 3*3*5*5*5
2. 2*2*7*7
3. 5*5*7*7
---------
Hint:
There are two 3's.
There are 3 5's.
RELATED QUESTIONS
Rewrite (5^-3)(7^2)/(5^6)(7^-8) using positive... (answered by MathLover1)
rewrite the sum using summation notation:
1, -2, 3, -4, 5, -6, 7,... (answered by Edwin McCravy)
[7-(3-2(7-5)+5)]+5 (answered by stanbon)
(a -2 b)4.... -2 and 4 are the exponents....
(-4c -3)5.... 5 is the only exponent...
73 (answered by richard1234)
3 - 2 5/7 =... (answered by rfer)
3/7+2/5= (answered by rfer)
3/5 +... (answered by jhunjiro)
-5[7-2(-3)] (answered by Alan3354)
The problem says
Stefan wants to ass (3 5/7 + 1 1/5) + 2 1/7. He uses the Commutative (answered by Alan3354)