SOLUTION: Factor completely
21x^2 + 33x + 12
Thank You!!!
Algebra.Com
Question 48798: Factor completely
21x^2 + 33x + 12
Thank You!!!
Answer by saltzy57(8) (Show Source): You can put this solution on YOUR website!
first we have to find the common multiple of the coefficient 21,33,and 12...answer =3
Now we rewrite the problem like this
3* (7x^2+11x+4)...
can be rewritten as follows:
3*(7x+4)*(X+1)
Good Luck and fun!
mike
RELATED QUESTIONS
How do I: Factor completely : 6x^2+33x+15
Thank you... (answered by lynnlo)
28. Factor completely. 21x2 + 33x + 12
(answered by checkley71)
Factor Completely:... (answered by mananth,Alan3354)
Factor completely:... (answered by jim_thompson5910)
Factor completely -9 + 18x^2 + 21x Please show step by step the factoring process, thank (answered by edjones)
completely factor... (answered by mananth,stanbon)
Rewrite the middle term as the sum of two terms and then factor completely
15X^2-21x+6
(answered by stanbon)
How do I factor this by grouping {{{35x^3-20x^2+21x-12}}}? Thank you. (answered by Earlsdon,JBarnum)
Factor completely. 15x^2 – 21x +... (answered by bucky,jim_thompson5910)