# SOLUTION: (-2) to the 5th power + (-5) to the 2nd power. I get really confused on how to do these. I have tried over and over again and I still can't get the right answer.

Algebra ->  Algebra  -> Exponents -> SOLUTION: (-2) to the 5th power + (-5) to the 2nd power. I get really confused on how to do these. I have tried over and over again and I still can't get the right answer.      Log On

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 Algebra: Exponents and operations on exponents Solvers Lessons Answers archive Quiz In Depth

 Question 482001: (-2) to the 5th power + (-5) to the 2nd power. I get really confused on how to do these. I have tried over and over again and I still can't get the right answer.Found 2 solutions by MathLover1, josmiceli:Answer by MathLover1(6815)   (Show Source): You can put this solution on YOUR website! ...be careful with negative sign: Answer by josmiceli(9819)   (Show Source): You can put this solution on YOUR website! You can always write these out the long way ( if the numbers aren't very big ) and look at them The main thing to notice is that there are an odd number of (-2)'s and an even number of (-5)'s Think of the (-2)'s grouped in pairs with one left over (-2)*(-2) this is positive (-2)*(-2) also positive (-2) this is negative So, you have (+) x (+) x (-) = (-) --------------------------- What if it was ? You would pair these up the same way, so you'd have a bunch of (+) x (+) x (+) . . . etc and one (-) left. that would give you a minus result -------------------- Back to your problem, then and OK?